Power plants FG WILSON
Installation of the generator unit
The generator unit is delivered fixed on a fixed base, which ensures a precise combination of the actual generator and the engine. It is only necessary to install the unit in place (in the case of large units – on vibration isolators) and align it (Fig. 4.1.)
Figure 4.1. Reducing the level of vibrations
Vibration isolation
It is recommended that the unit be mounted on vibration isolation pads to prevent the reception or transmission of dangerous and unwanted vibrations. If low vibration levels are acceptable, rubber mats can be used. For a higher level of vibration suppression, steel springs are used together with rubber shock absorbers. In small generator sets, these vibration isolators should be located between the motor/alternator and the base. The base, in turn, is securely attached to the floor. For large units, the motor/alternator unit must be rigidly connected to the base frame with vibration isolators installed between the base and the floor. Further vibration reduction can be achieved by providing flexible connections between the engine and fuel lines, the exhaust system, the radiator air line, the routing of power and control cables in cable ducts, and other external plug-in systems.
Loading on the floor
The load on the floor depends on the total mass of the generating set (including the mass of fuel and water), as well as the number and size of insulators. In the case of direct installation of the base on the floor, the load on the floor is calculated as follows:
Load on the floor = Total weight of the unit ÷ Area of the base of the frame
With vibration isolation between the base and the floor, if the load is evenly distributed among all isolators, the load on the floor is calculated as follows:
Load on the floor = Total weight of the generator ÷ (Isolator area × No. of insulators)
Thus, the load on the floor can be reduced by increasing the number of insulators.
If the load is unevenly distributed, then the maximum pressure on the floor will be under the insulators supporting the main part of the unit (it is assumed that all insulators have the same size):
Maximum pressure on the floor = Max. load on the insulator ÷ Area of the insulator